Question

A stone is dropped from the top of a tower reaches the ground in 4 second.Find the height of the tower.​

Answer 1

Answer:

• Height of the tower = 78.4 m

Explanation:

Stone is dropped from the top of a tower and reaches ground after 4 sec

so,

• Initial velocity of stone, u = 0
• Time taken by stone to reach the ground, t = 4 s
• Acceleration due to gravity, g = 9.8 m/s²

We need to find

• Height of tower, s =?

In this case the distance travelled by stone before reaching the ground will be the height of tower

therefore,

Using second equation of motion

→ s = u t + 1/2 g t²

[ Where s is distance covered, u is initial velocity, g is acceleration due to gravity and t is time taken ]

→ s = ( 0 ) ( 4 ) + 1/2 ( 9.8 ) ( 4 )²

→ s = 0 + 4.9 × 16

→ s = 78.4 m

Therefore,

• Height of the tower would be 78.4 meters.

Answer 2

Solution : -

= Time Taken by the stone is 4 seconds .

By Equation s = ut + 1/2 at² :

= s = 0 × 4 + 1/2 (9.8) × 4 × 4

= s = 0 + 9.8 × 2 × 4

= s = 9.8 × 6

= s = 78.4 m

Therefore , Height of Tower is 78.4 m