Question

A stone is dropped from the top of a tower. The
stone touches the ground after 5 sec. Height of
a tower is ------m.​

Answer 1

Answer:

Given,

u=0m/s

g=9.8m/s^2

t=10s

From 2nd equation of motion,

s=ut+1/2at^2  

h=0×0−1/2gt^2

−h=− 1/2gt^2  

h=1/2 ×9.8×10×10

h=490m