Question

A stone is dropped from the top of a tower travel 135 m in the last second of its journey the height of the​

Answer 1

Explanation:

Let total time be n

Last second = n-1

Apply 4th law of motion

For n second

u+a/2(2n-1)

For (n-1) second

u+a/2(2(n-1)-1)

u+a/2(2n-3)

u=0 a= 10 m/s² tower height =135 m

0+10/2(2n-3)=135

10n-15=135

n=15 sec