A stone is dropped from the top of a tower. When it crosses a point 5 m below the top, another stone is let fall from a point 25 m below the top. Both stones reach the bottom of the tower simultaneously. Find the height of the tower
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Answer:
displacementofthefirststonewhensecondisdropped=5m,thustime
differenceindroppingofthestonesist=
g
2h
=1s
h=
2
1
gt
2
=
2
1
g(t−1)
2
+25⇒t=3s
thus,h=45m
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