A stone is dropped from the top of the tower 50m high. Simultaneously another stone is thrown upward with a speed of 20m/s. Calculate the time at which both the stone cross each other.
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Answered by
11
take height of tower as H =50m
and time of crossing t
for falling stone apply ut+1/2at2
and for upward thrown stone ut-1/2at2
put value of time same and get answer.
and time of crossing t
for falling stone apply ut+1/2at2
and for upward thrown stone ut-1/2at2
put value of time same and get answer.
balajeevish:
distance covered by lower stone is x then upper stone will be50-x
Answered by
1
Explanation:
ut-1\2
thanks thanks....
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