Question

A stone is dropped from the top of the tower and reaches the ground in 3 sec . Then the height of the tower is what?
(g=9.8m/s^2)

Answer 1

Answer:

height of the tower is 44.1m

Explanation:

Given:

Time taken by the stone to reach the ground = 3 sec

U = 0 [dropped]

To find : height of the tower

Solution:

Using Newton's 2nd equation of Uniform motion

$h = ut + \frac{1}{2} a {t}^{2}$

Putting in the values

$h = 0 \times 3 + \frac{1}{2} \times 9.8 \times {3}^{2} \\ \\ h = \frac{1}{2} (9.8)(9) \\ \\ h = 44.1m$

height of the tower is 44.1m

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Answer 2

Answer:

44.1 m

Explanation:

use, h = ut + 1/2 at^2 formula

here:

u = 0

t = 3

a = 9.8

substitute the values and you'll get 44.1 m