Physics, asked by sandeepawasthi72, 1 year ago

a stone is dropped from the top of tower and reach the ground in 3 second caluiate height of tower and velocity with which it reached to ground (take acceleration 10m\second

Answers

Answered by anisha1764
1

Answer:

HEY MATE HERE is YOUR ANSWER

Attachments:
Answered by chethmidissanayake
2

Answer:

Explanation:

initial velocity=0

time=3s

gravitational acceleration=10

v=u+at

v=0+10*3

v=30ms-1

s=ut+1/2at*t

s=0+1/2*10*3*3

s=45m

Similar questions