Question

A stone is dropped from top of a tower of height 180 m above the ground if g=10 m/s² then time taken by the stone to reach on the ground is


❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ
❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ
❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​

Answer 1

Answer:

• 6 second is the required answer .

Step-by-step explanation:

According to the Question

It is given that,

• Height of stone ,h = 180m
• Acceleration due to gravity ,g = 10m/s²
• Initial velocity ,u = 0m/s

we have to calculate the time taken by stone to reach on the ground .

So, we apply here the kinematics equation

• h = ut + 1/2gt²

by putting the value we get

➻ 180 = 0×t + 1/2 × 10 × t²

➻ 180 = 0 + 5×t²

➻ 180 = 5t²

➻ 180/5 = t²

➻ 36 = t²

➻ √36 = t

➻ 6 = t

➻ t = 6s

• Hence, the time taken to reach on the ground is 6 second.

Answer 2

$180 = 0 + \frac{1}{2} \times 10 {t}^{2} \\ \\180 = 5 {t}^{2} \\ \\ \\ 180 \div 5 = {t}^{2} \\ \\ \\ \\ 36 = {t}^{2} \\ \\ \\ 6 = t$

6 Second .