Question

A stone is dropped from top of a tower ,reaches ground in 4s .Height of tower if (g=10 m/s^2) ?

Answer 1

QUESTION-:

A stone is dropped from top of a tower ,reaches ground in 4s .Height of tower if (g=10 m/s²) ?

EXPLANATION-:

• initial velocity(u)=0 m/s    (Since the ball is dropped from rest)
• Time(t)=4 s
• Acceleration=g=10 m/s²

Using 2nd equation of kinematics(free fall)-:

$\bf \red\bigstar \: \: \orange{ \underbrace{ \underline{ \bf\;\blue{ s=\frac{1}{2}at^2}}}}$

Putting values-:

→s=1/2×10×(4)²

→s=5×16

$\dashrightarrow \boxed{\bf\;s=80\;m}$

The height of tower is 80 metres .

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