Question

a stone is dropped from tower of height 10m final velocity of stone before it touch​

Answer 1

Using the formula   $v^{2} =u^{2} +2as$

Given that it is dropped.So u=0

Consider a=g=10m/s^2

$v^{2} =2*10*10$

$v^{2} =200$

$v=10\sqrt{2} m/s$