A stone is dropped in a well of depth 500 m and a sound is heard after 12 seconds. Then what is the speed of sound
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the speed of sound in this particular case is 250m/s
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Answer: 250m/s
Explanation:
Using newton's 3rd eq^n of motion:-
s=ut+1/2at^2
500=0+1/2 (10) (t)^2
500=1/2 (10) (t)^2
t^2=(500*2)/10
t= root(100) s=10s {here,t is time of sound}
12 s=10 s+X s
X s=2 s
Now, as V=S/t :-
V=500/2= 250m/s
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