Question

A stone is dropped in to well 44 m deep &:the sound of splashbs heaed fter 3.11 sec find the speed of sound in air

Answer 1

By second equation of motion

S=ut+1/2at^2

the stone is initially at rest,so

S=1/2at^2

44=1/2•10•t^2

t=2.96

So, the stone hit the well in 2.96 seconds.

Now

3.11-2.96=0.15 seconds

So, the sound was heared in 0.15 seconds and distance is 44 m .

So,

Distance =speed •time

Speed = Distance/time

Speed = 44/0.15

Speed =293.33

So the speed of sound in air is 293.33 m/s