Question

A stone is dropped into a deep well and is heard to hit the water 2 s after being dropped. Determine the depth of the well

Answer 1

Answer:

Given, acceleration of stone is a=g=9.8m/s

2

Initial velocity is u=0m/s

Time for hitting water is t=3.41s

If d be the depth of the well.

Using d=ut+at

2

/2,

∴ d=0(3.41)+0.5(9.8)(3.41)

2

=56.98∼57m