A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped.
Determine the depth of the well.
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1
Given, acceleration of stone is a=g=9.8m/s
2
Initial velocity is u=0m/s
Time for hitting water is t=3.41s
If d be the depth of the well.
Using d=ut+at
2
/2,
∴ d=0(3.41)+0.5(9.8)(3.41)
2
=56.98∼
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2
Initial velocity is u=0m/s
Time for hitting water is t=3.41s
If d be the depth of the well.
Using d=ut+at
2
/2,
∴ d=0(3.41)+0.5(9.8)(3.41)
2
=56.98∼
Hope it helps u
Mark me brainiest pls
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