Question

A stone is dropped into a deep well and takes 4 seconds to reach the bottom a how deep is the well
b how fast is the stone moving just before it hits the bottom

Answer 1

Answer:

Explanation:

Please mark as brainliest :)

Answer 2

Answer:78.4

Explanation:given Vi=0

t=4s

X=?

Use equation of motion

X=Vi×t +(0,5)at^2

=0(4)+(0,5)(9.8)(4)^2

=78,4

b Vf^2=Vi^2+2aX

=(0)^2 +2(9,8)(78,4)

=1536,64

=square root 1536,64

Vf=39.2m/s