a stone is dropped into a lake from a tower 500m high.the sound of splash will be heard by the man approx. after (a)11.5sec (b)10 sec (c)21 sec (d)14 sec
Answers
Answered by
142
We know that
s = ut +1 /2 at²
here
u = 0
a = g
s = 500m
so putting value in above equation
we get
t = 10s
Now
Velocity of sound in air 332m/s
time of sound travel = (t1 - 10)sec
Distance= sound ×time
500 = 332 × (t1 -10)
t1 = 11.5 sec
s = ut +1 /2 at²
here
u = 0
a = g
s = 500m
so putting value in above equation
we get
t = 10s
Now
Velocity of sound in air 332m/s
time of sound travel = (t1 - 10)sec
Distance= sound ×time
500 = 332 × (t1 -10)
t1 = 11.5 sec
Answered by
14
11.5 sec is correct answer
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