Question

a stone is dropped into a well and hits the water surface in 4s how Deep is the well and with what velocity the stone hit the water surface ?

Answer 1

Answer:

Explanation:

d(4)=1/2 g(4)²

=1/2(9.8)(16)

=78.4m deep as the water level

V=√2gh

=√2 x 9.8 x 78.4

=39.2 m/s as the velocity of the stone