Question

a stone is dropped into a well and its splash is heard at the mouth of the well after an interval of 1.45 second find the depth of the value of a given the given that velocity of sound in air at room temperature is equal to 332 metre per second​

Answer 1

Time taken by the stone to reach the water surface  can be calculated using the equation of motion

s = ut + ½ gt2

Here u = 0, s = 44 m , g = 9.8 m/s2

 

So

t = (2x44/9.8)½

        = 2.996 s ≈ 3 s

Therefore time taken by sound to travel this distance = 3.12 - 3 = 0.12 s

Speed of sound in air = distance covered/Time

                                           = 44 m/ (0.12 s)

                                           = 366.7 m/s

Answer 2

The dept of the well:- 9.9m