Question

A stone is dropped into a well in which the level of water is h below the top of the well .If v is velocity of sound, the time T after which the splash is heard is given by.

Answer 1

first of we'll find the time taken by stone to reach the surface of well.
h= gt^2/2
$t1 = \sqrt{ \frac{2h}{g} }$
and time taken by sound to come back is
$t2 = \frac{h}{v}$
Therefore,
$t = \sqrt{ \frac{2h}{g} } + \frac{h}{v}$

Answer 2

Answer:

***See the attachment ***