Physics, asked by harish2269, 1 year ago

A stone is dropped into a well in which the level of water is h below the top of the well. If v is velocity of sound, the time T after which the splash is heard is given by(a) T = \frac{2h}{v}(b) T = \sqrt{[\frac{2h}{g}]} + \frac{h}{v}(c) T = \sqrt{[\frac{2h}{v}]} + \frac{h}{g}(d) T = \sqrt{[\frac{h}{2g}]} + \frac{2h}{v}

Answers

Answered by guduuu
0
the answer is c part
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