Question

A stone is dropped into a well of 50m deep, and the sound of the splash is heard after 3.33 s. The velocity of the sound in air is (g = 9.8 m/s^2)

Answer 1

Answer:

357.14

Explanation:

$s = ut + \frac{1}{2} a {t}^{2}$

$50 = 0 + \frac{1}{2} \times 9.8 \times {t}^{2}$

$t = 3.19 \: sec \: (approx \: 3 \: sec)$

For reflected sound waves

d=vt

50=v(3.33-3.19)

50=v(0.14)

$v = \frac{50}{0.33}$

V=357.14 m/s

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