Physics, asked by lovelymaheshwari1974, 11 months ago

A stone is dropped into a well of 80m deep. The sound splash is heard 4.2 sec after the stone is dropped. The velocity of sound in air will? Help me please

Answers

Answered by khushidarji64
10

Depth of well S = 80m

a = - g = -10

u = 0 since the stone is dropped

S = ut + 0.5at^2 = 0+ 1/2 x -10 x t^2

80 *2/10 = t^2

t= 2 seconds

Given time = 4.2 s

Time taken by sound to travel 80m in air = 4.2-2 = 2.2s

Distance covered by sound in air= 80m

Speed of sound in air = 80/2.2

= 36.36m/s

The question seems to be wrong since actual value of speed of sound in air is approx 336 m/s

Answered by srihasinij
0

Answer:

36.36m/s

Explanation:

Depth of well S = 80m

a = - g = -10

u = 0 since the stone is dropped

S = ut + 0.5at^2 = 0+ 1/2 x -10 x t^2

80 *2/10 = t^2

t= 2 seconds

Given time = 4.2 s

Time taken by sound to travel 80m in air = 4.2-2 = 2.2s

Distance covered by sound in air= 80m

Speed of sound in air = 80/2.2

= 36.36m/s

The question is wrong as value of speed of sound in air is approx 336 m/s

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