A stone is dropped into a well of 80m deep. The sound splash is heard 4.2 sec after the stone is dropped. The velocity of sound in air will? Help me please
Answers
Depth of well S = 80m
a = - g = -10
u = 0 since the stone is dropped
S = ut + 0.5at^2 = 0+ 1/2 x -10 x t^2
80 *2/10 = t^2
t= 2 seconds
Given time = 4.2 s
Time taken by sound to travel 80m in air = 4.2-2 = 2.2s
Distance covered by sound in air= 80m
Speed of sound in air = 80/2.2
= 36.36m/s
The question seems to be wrong since actual value of speed of sound in air is approx 336 m/s
Answer:
36.36m/s
Explanation:
Depth of well S = 80m
a = - g = -10
u = 0 since the stone is dropped
S = ut + 0.5at^2 = 0+ 1/2 x -10 x t^2
80 *2/10 = t^2
t= 2 seconds
Given time = 4.2 s
Time taken by sound to travel 80m in air = 4.2-2 = 2.2s
Distance covered by sound in air= 80m
Speed of sound in air = 80/2.2
= 36.36m/s
The question is wrong as value of speed of sound in air is approx 336 m/s