Question

a stone is dropped into a well the sound of the splash is heard after 3.13sec . find the speed of sound in air g =10m/s

Answer 1

First we will find the distance the stone covers in 3.13 sec

we will use the second law of motion

s = ut + 1/2 at²

putting the values we get

s = 0 + 1/2*10*3.13²

  = 48.98

now the speed of the sound we will find by

s= 2d/t

s= 2*48.98/ 3.13

speed = 31.29 m/sec