Question

A stone is dropped is dropped from the top of a tower 500 m high into a pond of water at the base of the tower . when is the Splash heard at the top ? Given,g= 10 m s‐² and speed of sound = 340 m s‐²...?????!

Answer 1

Answer:

Height of the tower, s = 500 m

Velocity of sound, v = 340 m sˆ’1

Acceleration due to gravity, g = 10 m sˆ’2

Initial velocity of the stone, u = 0 (since the stone is initially at rest)

Time taken by the stone to fall to the base of the tower, t1

According to the second equation of motion:

S = ut1 + 1/2gt12

500 = 0 x t1 + 1/2 x 10 x t12

t12 = 100

t1 = 10s

Now, time taken by the sound to reach the top from the base of the tower, t2= 500/340 = 1.47 s

Therefore, the splash is heard at the top after time, t

Where, t= t1 + t2 = 10 + 1.47 = 11.47 s.

Answer 2

Answer:

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