Question

a stone is dropped on the moon from a height of 1.4m if the acceleration due to gravity on the moon is 1.67m/s^2 determine the time taken for the feather to reach the surface of the moon​

Answer 1

Explanation:

Given, acceleration a=1.67m/s

2

Distance covered by feather d=1.40m

Initial velocity u=0m/s (assume heather falls from rest)

Using formula S=ut+at

2

/2,

1.40=0(t)+

2

1

(1.67)t

2

or t

2

=2.8/1.67=1.68

Answer 2

Given, acceleration a=1.67m/s

2

Distance covered by feather d=1.40m

Initial velocity u=0m/s (assume heather falls from rest)

Using formula S=ut+at

2

/2,

1.40=0(t)+

2

1

(1.67)t

2

or t

2

=2.8/1.67=1.68

⟹ t=

1.68

=1.29s