Question

A stone is dropped on the moon from a height of 30 m. The acceleration due to gravity on the moon is g6. Determine the approximate time taken by the stone to fall on the surface of the moon. (Take g=10 m/s2 )​

Answer 1

Given:

A stone is dropped on the moon from a height of 30 m. The acceleration due to gravity on the moon is g/6.

To find:

Time taken to reach ground ?

Calculation:

• Acceleration value on moon = g/6 = 10/6 = 1.67 m/s².

Applying EQUATIONS OF KINEMATICS:

$h = ut + \dfrac{1}{2} a {t}^{2}$

$\implies \: 30 = 0 + (\dfrac{1}{2} \times 1.67 \times {t}^{2} )$

$\implies \: 30 =0.83 {t}^{2}$

$\implies \: {t}^{2} = 36.14$

$\implies \: t = \sqrt{36.14}$

$\implies \: t = 6.012 \: sec$

So, time taken is 6.012 seconds.