Question

A stone is dropped on the surface of the moon from
a height of 1.40 meters. The acceleration of gravity
on the moon is 1.67 m/s 2. Determine the time for
the stone to fall to the surface of the moon.​

Answer 1

Answer:

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Explanation:

Given: vo=0 m/s d=1.40 m a=1.67 m/s2

Unknown: t=???

Relevant Equation: d = vo•t + ½•a•t2

Solution: 1.40 m = (0 m/s)•(t) + ½•(1.67 m/s2

)•t2

1.40 m = (0.835 m/s2

)•t2

t

2 = (1.40 m) / (0.835 m/s2

)

t = SQRT(1.6766 … s2

) (SQRT = square root)

Answer: 1.29 s