a stone is falling freely the distance traveled in the last second is equal to that traveled in the first 3secs . then find out the time spent by the stone I air?
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s =ut + 0.5gt
2
_________1
In first 3sec, let it covers distance "d" m.
d=0.5g(3)
2
=4.5g
This distance is same as distance traveled in last second
So, according to formula,
S
n
=u+0.5a(2n−1)
4.5g=0.5g(2n−1)
Here, u=0 and n is number of seconds for which stone is in air.
∴n=5 sec
Substituting in eqn 1,
S= 122.5m
Explanation:
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