A stone is falling from a mountain. The velocity of the stone is given by V=9.8t.Draw it's graph and find the velocity of the stone'4' seconds after start
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Answer:
39.2m/s
Step-by-step explanation:
The velocity of the stone is given by the velocity function
v = 9.8t
where v is velocity of the stone after t seconds.
We need to find the velocity of the stone '4' second after start.
Substitute t = 4 in the given velocity function.
v = 9.8(4)
v = 32.2m/s
Therefore the velocity of the stone '4' second after start is 39.2 m/s.
For graph
v1 = 9.8
v2 = 9.8(2) = 19.6
v3 = 9.8(3) = 29.4
v4 = 9.8(4) = 39.2
Hope this will help you
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