A stone is gently dropped from a height of 80 m. If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the velocity of the stone when it will strike the ground and how much time will it take to reach there?
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USE
s=ut+1/2at^2
Take u =0 as stone is dropped
hence you will get time
Then use
v=u+at
here also u=0 as stone is dropped
hence you will get final velocity
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