Question

A stone is initially dropped from height 'h' at the equator and then it is
dropped from same height 'h' at the pole. It is observed that stone
reaches the ground quickly at the poles than at the equator. Justify the
observation. *​

Answer 1

Explanation:

ANSWER

Velocity, v=

2gh

Momentum, P=mv=m

2gh

P∝

h

P

1

P

2

=

h

1

h

2

=

h

2h

=

2

P

2

=1.414P

1

% change =

P

1

P

2

−P

1

×100%

=41.4%

Answer

Answer 2

Answer:

Velocity v=

2gh

....(i)

And

Momentum p=mv......(ii)

From (i) and (ii) we have

p∝

h

Here,

p

1

p

2

=

h

1

h

2

∴

p

1

p

2

=

h

2h

=

2

p

2

=1.414p

1

% change=

p

1

p

2

−p

1

×=41%