Question

A stone is let to fall from a balloon ascending with an acceleration f. After t time a second stone is dropped. Prove that the distance between the stones after time t' since the second stone is dropped is 1/2(f+g)t(t+2t').

Answer 1

Answer:

the distance between stone's after time is given is different to second stone.

Explanation:

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Answer 2

Answer:

1/2(f+g)t(t+2t')

Explanation:

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