A stone is let to fall from a building of height 80m. What will be the ratio of heights
fallen by the stone after 2s and 3s ?
Answers
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The distance an object moves, starting from rest, under a constant acceleration is equal to (1/2)at^2.* Gravitational acceleration changes with height; infinitely far from Earth, the acceleration is zero. Close to the Earth’s surface, the acceleration is a constant 9.81 meters per second per second.
But for any building built so far in history, the change in acceleration between top and bottom can be taken to be entirely negligible. This means that, in the case you are asking about, we can assume a = 9.81 meters per second per second.
So, let's take that 10 seconds and solve for the height. We have:
h = (1/2) a t^2 = (1/2) (9.81) (10)^2 = 490.5 meters
The building is 490.5 meters tall!
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*If you want to confirm that for yourself, you'll have to solve the differential equation (d/dt)^2 y = a, where a is a constant. If you don't know what that means, don't worry; based on the fact that you are asking this question, deriving this formula likely involves mathematics higher than you've learned.
Answer:
your answer is in attachment
