Question

A stone is projected from level ground with speed uu and at angle with horizontal. Some how the acceleration due to gravity (gg) becomes double (i.E, 2g2g) immediately after the stone reaches the maximum height and remains the same thereafter. Assume that the direction of acceleration due to gravity always vertically downwards. The total time of flight of particle is

Answer 1

Hello

Max height = u^2 sin^2 x/2g =s

​Time to reach ground can be obtained from s= gt^2/ . ( since u is 0 at top most point I.e in vertical direction).

ucosx multiplied by time = range.

Let final speed be v'.

Where v= 2gt

V'= v/siny

Horizontal veloity is not changed so v'cosy= ucosx

​from this u can get y

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