Question

A stone is projected from the ground with a velocity of 14m/s one second later
it clears a wall 2m high. the angle of projection is (g = 10m/s^2)
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I want solution please....................

Answer 1

Good evening,
here let the angle of projection be 'alpha'
therefore, Ux=14cos alpha and Uy=14sin alpha
after 1 sec.. i.e. t= 1 sec, it clears a wall 2 m high
therefore, height from ground(H)= 2m.
Applying formula, H=(uyt-gt^2)/2

2=[14cos alpha*1-10(1)^2]/2
4=14cos alpha-10
14=14 cos alpha
therefore, cos alpha = 1
therefore, alpha = O°
.. Hope this helps.
^_^
If you have any queries.. comment them down.

Answer 2

Refer The Attachment ⬆️

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Hope It Helps You ✌️