Question

a stone is projected from the ground with a velocity of 14ms-1.one second later it clears a wall 2m high .the angle of projection is (g= 10ms-2).

Answer 1

Answer:

the answer is 30 degree

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Answer 2

The angle of projection is 30°.

Given,

Projection velocity = u = 14 m/s

After 1 second, the ball crosses a 2 m wall

g = 10 m/s²

To Find,

The angle of projection (θ)

Solution,

For finding the angle of projection, the equation in the 'y' direction needs to be written down,

For 'y' direction, velocity is given as -

v = u*Sin θ = 14*Sin θ

Writing the 2nd equation of motion under gravitation for y direction -

s = ut + (1/2)at²

s here is the distance which is 2 m

t is the time which is given as 1 second

2 = 14*Sin θ(1) - (1/2)g(1)²

g = 10 m/s²   (given)

2 = 14*Sin θ(1) - (1/2)(10)(1)²

2 = 14*Sin θ - 5

2 + 5 = 14*Sin θ

Sin θ = $\frac{7}{14}$

θ = Sin⁻¹ ( $\frac{7}{14}$)

θ = Sin⁻¹ ( $\frac{1}{2}$)

⇒ θ = 30°

Therefore, the angle of projection is 30°.

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