A stone is projected from the ground with a velocity of 25m/s 2 second alter it just clear a wall of 5m high find angle of projection (g=10)
Answers
Answered by
95
Hello !
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y = u(y)t sin∅- 1/2gt²
y = 5 m
t = 2 seconds
u = 25m/s
g = 9.8 m/s²
so,
5 = 25 x 2 sin∅ - 1/2 x 9.8 x 4
5 = 50 sin∅ - 4.9 x 4
5 = 50 sin∅ - 19.6
24.6/50 = sin∅
0.492 = sin∅
0.5 = sin∅
sin∅ = sin 30°
∅ = 30°
____________________________________________________________
y = u(y)t sin∅- 1/2gt²
y = 5 m
t = 2 seconds
u = 25m/s
g = 9.8 m/s²
so,
5 = 25 x 2 sin∅ - 1/2 x 9.8 x 4
5 = 50 sin∅ - 4.9 x 4
5 = 50 sin∅ - 19.6
24.6/50 = sin∅
0.492 = sin∅
0.5 = sin∅
sin∅ = sin 30°
∅ = 30°
Answered by
46
Answer:
theta = 30°
Explanation:
s= ut sin theta - 1/2 gt^ 2
s=5
t=2
u=25
g= 10
put these values in above equation
5=25×2 sin theta -1/2×10×2×2
so,
sin theta = 1/2
theta = 30°
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