Question

A stone is projected horizontal 30m/s from the to 45m high.At what angle with horizontal the stone strokes yhe horizontal ground at same level of foot of tower?

Answer 1

given
u in x axis is 30m/s
height of tower is 45m
u in y axis is 0

solve ; v^2 - u^2 = 2as. in y direction

v^2 - 0 = 2×10×45

v^2 = 900

v = 30m/s

since velocity in x direction remains 30

therefore; tan theta = 30/30
tan theta = 1

therefore the with horizontal is 45

Answer 2

given
u in x axis is 30m/s
height of tower is 45m
u in y axis is 0

solve ; v^2 - u^2 = 2as. in y direction

v^2 - 0 = 2×10×45

v^2 = 900

v = 30m/s

since velocity in x direction remains 30

therefore; tan theta = 30/30
tan theta = 1

therefore the with horizontal is 45

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