Physics, asked by Anonymous, 7 months ago

A stone is projected horizontally from a building with a
velocity 6ms. After 0.8s, the magnitude of velocity of
ball would be (Take g = 10 m/s2)​

Answers

Answered by poojakumaresh26
2

initial velocity ( u ) = 6m/s

t = 0.8 seconds

a = g = 10m/s^2

final velocity =?

using v = u + at

v= 6+ 10* 0.8

v = 14 m/s

Answered by arunakmanju875
1

Answer:

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