Question

A stone is projected horizontally from a tower of height 49m. Calculate velocity after 1 s and velocity with which it strikes the ground.
Please answer , i have a test

Answer 1

Explanation:

Given,

h max=49m

a=10m/s^2

u=0

t=1 sec

v=u+at

v=0+10(1)

v=10m/s

So, velocity after one second is 10m/s

Now,

v^2=u^2+2(a)(s)

v^2=0+2(10)(49)

v^2=20(49)

v^2=980

v=√980

v=31.30m/s

Velocity with which it strikes the ground=31.30m/s.

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