Question

a stone is projected horizontally from the top of a tower of height 78.4m with a velocity of 10 m/s at what distance from the base of the tower it will strike the ground​

Answer 1

Answer:

40 m

Explanation:

Here is the step-by-step explanation

Let the stone hit the ground after t seconds-

therefore the horizontal distance covered = velocity in the horizontal direction. t sec.

R = v. t = 10 m/s .t or t = R/10 s

however, in the same time interval, it falls a height h = 78.4 m; starting from initial velocity in vertical direction=0

therefore h = 78.4 m = (1/2).g. t^2 = (1/2).g.{R^2/100}

Range R = sqrt {78.4 . 2. (100 /9.8)} = sqrt(1600) =40 m

Hope it helps!