a stone is projected horizontally from the top of a tower of height 78.4m with a velocity of 10 m/s at what distance from the base of the tower it will strike the ground
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Answer:
40 m
Explanation:
Here is the step-by-step explanation
Let the stone hit the ground after t seconds-
therefore the horizontal distance covered = velocity in the horizontal direction. t sec.
R = v. t = 10 m/s .t or t = R/10 s
however, in the same time interval, it falls a height h = 78.4 m; starting from initial velocity in vertical direction=0
therefore h = 78.4 m = (1/2).g. t^2 = (1/2).g.{R^2/100}
Range R = sqrt {78.4 . 2. (100 /9.8)} = sqrt(1600) =40 m
Hope it helps!
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