Question

A stone is projected horizontally with 20m/s and it hits the vertically wall in front of stone at a distance of 60m. Taking projection point of stone as a origin of .r-y plane find the co-ordinates of point of hit on the vertical wall:​

Answer 1

a stone is projected horizontally with 20 m per second from ... Taking projection point aa origin ... Velocity remains 20 m/s ... Distance covered in downward s=5x9=45m

Answer 2

Answer:

Initial Vertical velocity of first stone is u

1

=0,

Initial vertical velocity of second stone is u

2

=0,

Stone is dropped from cliff, height= −h=-20 m,

Let time taken by first stone to reach the ground is t

1

and by second stone is t

2

.

Using s=ut+

2

1

at

2

,

⇒−h=ut

1

−

2

1

gt

1

2

⇒t

1

=

g

2h

......1

⇒−h=ut

2

−

2

1

gt

2

2

⇒t

2

=

g

2h

......2

Comparing equations 1 and 2, ⇒t

1

=t

2

Both the balls hit the ground at same time.