Question

a stone is projected in air. its time of flight is 3 sec and the range is 150. maximum height reached by the stone is​

Answer 1

Answer:

Explanation: T=2U/g

=U=15 m/s

Hmax= u^2/2g

: 15×15/2×10

ANSWER: 11.25m

Answer 2

The maximum height reached by the stone is 11.03 m​.

Explanation:

The time of flight of a projectile motion is given as

$T=\frac{2u\sin\theta}{g}$

$\frac{gT}{2} =u\sin\theta$

The maximum height is given as

$H=\frac{u^2\sin^2\theta}{2g}$

Here, u is the initial velocity and $\theta$ is the angle of projection and g is the acceleration due to gravity.

So,

$H=\frac{\frac{g^2T^2}{4} }{2g}$

$H=\frac{gT^2}{8}$

Given T =3 s and take $g=9.8m/s^2$ .

Substitute the given values, we get

$H=\frac{9.8m/s^2\times(3s)^2}{8}$

H = 11.03 m.

Thus, the maximum height reached by the stone is 11.03 m​

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