Question

a stone is projected up vertically with a velocity of 9.8 ms. how much times is remains in air​

Answer 1

Answer:

Given,

Take initial velocity u=9.81m/s

Acceleration is downward a=−g=−9.81m/s

2

When the body come to the ground, it has equal velocity in magnitude but opposite in direction.

Final velocity v=−u

Apply kinematic equation

v=u+at

−u=u−gt

t=

g

2u

=

9.81

2×9.81

=2sec

Explanation:

this is the correct answer

Answer 2

Answer:

Let's take the acceleration due to gravity as 9.8m/s^2 as well.

So, when the stone gets projected upwards, it gets slower and slower as gravity pulls it towards the Earth, till it momentarily stops and then drops back down.

The time interval between the stone leaving the ground and falling back on it is called the Time of Flight.

The expression used to calculate this time is 2u/g

Here, u is the vertical velocity of the projectile and g is the acceleration due to gravity.

So, in this case

T = 2*9.8/9.8 = 2sec

Explanation:

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