a stone is projected vertically up from the ground with velocity 40 m/s.the interval of time between the two instants at which the stone is at a height of 60 m above the ground is (g=10m/s^2
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Explanation:
Correct option is A)
60=ut−21gt2
60=40t−5t2
⇒5t2−40t+60=0
t1+t2=540=8
t1t2=560=12
t1=6,t2=2
Hence, interval of time =t1−t2=6−2=4 s.
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