A stone is projected vertically, up from the top of the tower at a velocity of 9.8 m/s it reaches the foot of the building in 4sec what is the height of the tower and the velocity of the stone when it reaches the ground. (g = 9.8 m/s²).
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Correct option is
D
29.4 m
From second equation of motion, s=ut+at
2
/2
Assume upward direction to be positive.
u=4.9 m/s, t=3 sec, a=−9.8 m/s
2
s=4.9×3−9.8×3
2
/2
s=−29.4 m
Height = 29.4 m
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