Question

A stone is projected vertically upwards from the ground reaches a maximum height h. When it is at a height 3h/4,the ratio of its kinetic energy nd potential energy is​

Answer 1

Answer:

We now that energy is always conserved.

So, at a height 3h/4 , it will have both kinetic and potential energy.

Potential energy is due to position, h=3h/4 is:

So , PE=mgh

⇒PE=

4

3mgh

Now, kinetic energy =

2

1

mv

2

Also, by third equation of motion, v

2

=u

2

+2gh

Here for kinetic energy h=h/4

⇒v

2

=

2

gh

Substituting the value of v

2

in the equation of kinetic energy,

We get, KE=

4

mgh

So, KE:PE=

4

mgh

×

3mgh

4

⇒KE:PE=1:3

Answer 2

Answer:

We now that energy is always conserved.

So, at a height 3h/4 , it will have both kinetic and potential energy.

Potential energy is due to position, h=3h/4 is:

So , PE=mgh

⇒PE=

4

3mgh

Now, kinetic energy =

2

1

mv

2

Also, by third equation of motion, v

2

=u

2

+2gh

Here for kinetic energy h=h/4

⇒v

2

=

2

gh

Substituting the value of v

2

in the equation of kinetic energy,

We get, KE=

4

mgh

So, KE:PE=

4

mgh

×

3mgh

4

⇒KE:PE=1:3

Explanation:

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