Question

a stone is projected vertically upwards with a velocity 55m/s find the distance covered in 6th second

Answer 1

$\huge\underline\mathfrak\red{Answer:-}$

1.10m.

STEP BY STEP EXPLANATION:-

For the 6th second, we need to find , first the velocity after 5 seconds.

V=55–5X9.8=55–49=6m/s.

This will go to 0 in only part of a second, t=6/9.8=0.612s

D=1/2*a*t^2=(9.8*(0.612)^2)/2=1.84m, upwards.

For the remaining 0.388s, the ball travels d=1/2*9.8*(0.388^2)=0.737m downward.

So, net distance travelled is roughly 1.10m.

Answer 2

Answer:

330 m

Explanation:

55×6=330m distance covered by stone