Question

A stone is projected with a velocity
20 2 m/s at an angle of 45° to the
horizontal. The average velocity of stone
during its motion from starting point to its
maximum height is (in m/s)​

Answer 1

average velocity is given by

time

displacement

displacement till highest point will be (

2

R

,H) in horizontal and vertical direction respectively.

As given V=20

2

, θ=45

then H=

2g

V

2

sin

2

θ

, R=

g

V

2

sin2θ

,

time=

g

Vsinθ

H=20m,

2

R

=40m,T=2

average velocity =

2

20

2

+40

2

=10

5

m/s