Question

A stone is projected with a velocity of 20m/s angle of 30 degrees of to horizontal - After 1.5 sec theta find its horizontal Distance and vertical height from its standing points

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Answer 1

Answer:

Sy=ut−21gt2

h=Sy=20sin30o×5−21×10×(5)2

h=50−125=−75m (minus sign just indicates that the displacement is in downward direction)

hmax=2gu2sin2θ=2×10(20)2sin2300=5m

Hence, maximum height attained by projectile =h+hmax=75+5=80 m